Problem 1-1

We will provide a sample solution on how to solve for a 1sec for each of the running time. 1sec = 1000millisecond = 1000000microsecond 1sec = 10^6microsecond Solving for lgn = 10^6 solving for Solving for With an initial guess of 10^6, we can use Newton-Raphson method to get a solution Solution is: 62746.12646969076 See https://replit.com/@AleemIsiaka/nlgn-106#main.py Solving for n^3 = 10^6 Solving for Solving for n! n! = n! = 1*2*3*4….n = We could pick a number as a guess, and check if the value is within . if n = 10 10! = 3628800 (> ) 9! = 637120 (< ) Hence n = 9, such that We could do same for the rest of the time, changing the time value but running similar operations for the running times.